A) it is converted to the tetrafluoride that bubbles out as a gas.
B) It is precipitated as the carbide.
C) It is precipitated as sodium silicate.
D) It is precipitated as iron silicate.
E) It is converted to silicon dioxide and becomes part of the slag.
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Multiple Choice
A) 2
B) 5
C) 3
D) 4
E) 1
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Multiple Choice
A) 4
B) 2
C) 3
D) 5
E) 1
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Multiple Choice
A) increased surface luster
B) increase in malleability and corrosion resistance
C) decrease in conductivity and increase in brittleness
D) decrease in melting point and increase in ductility
E) increase in hardness and strength, decrease in ductility
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Multiple Choice
A) the use of aqueous solutions to extract metals from their ores.
B) the use of water to cool molten metals.
C) the use of high temperature processes to concentrate and refine metals.
D) the use of high temperature processes to make alloys.
E) the use of water to locate underground ore deposits.
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Multiple Choice
A) Ni is oxidized preferentially over Cu, and Ni2+ is reduced much less readily than Cu2+, so Ni is separated as Ni2+ in the electrolyte solution.
B) Cu is oxidized preferentially over both Ni and Ag, so both Ni and Ag metals are separated as sludges below the anode.
C) Ag is oxidized preferentially over Cu, and Ag+ is reduced much less readily than Cu2+, so Ag is separated as Ag+ in the electrolyte solution.
D) Ag is oxidized preferentially over Cu, and Ag+ is reduced much more readily than Cu2+, so Ag plates out with Cu at the cathode and cannot readily be removed from impure copper.
E) Both Ni and Ag are oxidized preferentially over Cu and Ni2+, and Ag+ is reduced much less readily than Cu2+, so Ni and Ag are separated as Ni2+ and Ag+ in the electrolyte solution.
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Multiple Choice
A) an insulator, because all the lower energy band orbitals are filled and the gap between the lower and higher bands is large.
B) a conductor, because its lower energy band orbitals are only partially filled.
C) a conductor, because all the lower energy band orbitals are filled and the gap between the lower and higher bands is large.
D) a semiconductor, because the gap between the filled lower and empty higher energy bands is relatively small.
E) a semiconductor, because the gap between the filled lower and empty higher energy bands is large.
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Essay
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Multiple Choice
A) green.
B) yellow.
C) orange.
D) colorless.
E) blue.
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Multiple Choice
A) 2
B) 1
C) 5
D) 3
E) 4
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Multiple Choice
A) pure iron.
B) a liquid at room temperature.
C) oxidized iron.
D) an alloy of iron.
E) a mixture of iron and silver.
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Multiple Choice
A) semiconductor
B) conductor
C) alloy
D) nonmetal
E) insulator
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Multiple Choice
A) the gold recovered in this way has higher purity than gold recovered in other ways.
B) the process requires only one step.
C) the method can be used to locate underground gold deposits.
D) gold can be recovered from very low- grade ores by this method.
E) the process is environmentally safe.
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Short Answer
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Multiple Choice
A) Au(CN) 4- (aq) and OH- (aq)
B) Au(CN) 2- (aq) and OH- (aq)
C) AuCN (s) and OH- (aq)
D) AuCN (s) and H2O2 (aq)
E) Au(CN) 3 (s) and OH- (aq)
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Multiple Choice
A) alloying.
B) pyrometallurgy.
C) roasting.
D) electrometallurgy.
E) hydrometallurgy.
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Multiple Choice
A) the cryolite provides a source of sodium ions.
B) the melting point of pure, anhydrous aluminum oxide is too high.
C) the cryolite provides the necessary fluoride ions.
D) the cryolite actually provides the aluminum that is to be reduced.
E) in pure, molten Al2O3, the aluminum would be oxidized rather than reduced.
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Multiple Choice
A) CCl2
B) K2CrO4
C) (NH4) 2Cr2O7
D) Cr(NO3) 3
E) CrCl3
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Multiple Choice
A) +1
B) 0
C) +6
D) +2
E) +4
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Short Answer
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